So back in February Jeff Atwood over at codinghorror.com was talking about a puzzle to give prospective new-hires when interviewing them entitled “Fizzbuzz”. You can read more about it here.

So with a little thought I decided to solve the fizzbuzz puzzle using Rudy and an Array.

count = 0
100.times do
  count += 1
  fb = []
  fb << "Fizz" if (count % 3) == 0
  fb << "Buzz" if (count % 5) == 0
  fb << count if (count % 3) != 0 and (count % 5) != 0
  puts (fb.join "")
end

For those of you that are curious as to why I used a local variable of count rather then the index identifier, is because the article by Jeff Atwood requests a loop from 1-100 and Ruby starts looping at 0.